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A box has 5 blue and 4 red balls. One ball is drawn at random and not replaced. Its colour is also not noted. Then another ball is drawn at random. What is the probability of the second ball being blue?

0 5 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    This is a  Short Answer Type Questions as classified in NCERT Exemplar

    Sol:

    G i v e n     t h a t     t h e     b o x     h a s     5     b l u e     a n d     4     r e d     b a l l s . L e t         E 1 = T h e     e v e n t     t h a t     I     b a l l     d r a w n     i s     b l u e                       E 2 = T h e     e v e n t     t h a t     I     b a l l     d r a w n     i s     r e d a n d         E = T h e     e v e n t     t h a t     a     I I     b a l l     d r a w n     i s     b l u e ∴               P ( E 1 ) = 5 9 ,     P ( E 2 ) = 4 9 ,     P ( E / E 1 ) = 4 8     a n d     P ( E / E 2 ) = 5 8 ∴                   P ( E ) = P ( E 1 ) . P ( E / E 1 ) + P ( E 2 ) . P ( E / E 2 )                                                   = 5 9 × 4 8 + 4 9 × 5 8 = 2 0 7 2 + 2 0 7 2 = 4 0 7 2 = 5 9 H e n c e ,     t h e     r e q u i r e d     p r o b a b i l i t y     i s     5 9 .

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