A car running from point P1 to point P2 meets with an accident 50 km from point P1, after which it travels with three- fifths of its original velocity and arrives 3 hours late at point P2; if the accident had occurred 50 km further on, it would have been only 2 hours late. Find the distance from point P1 to point P2.

Option 1 -

200 km

Option 2 -

180 km

Option 3 -

160 km

Option 4 -

240 km

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Let the distance be x km and speed be y km/hr and t be the time in hours. Then the equation will be x = yt …. (1),

    Therefore,  50y+ [x50]3y/5=t+3..... (2)

    Also,  100y+ [x100]3y/5=t+2..... (3)

    On solving the above equations, we get speed is 1003 km/hr time is 6 hrs, and distance is 200 km.

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