A number of two digits exceed the number formed by reversing the digits by 18. If the sum of the digits is 10, find the number.
A number of two digits exceed the number formed by reversing the digits by 18. If the sum of the digits is 10, find the number.
Option 1 -
73
Option 2 -
46
Option 3 -
64
Option 4 -
82
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:Let X be the units digit of the number and Y be the tens digit.
The number is 10Y + X
The reversed number is 10X + Y
(10Y + X) – (10X + Y) = 18 or 9Y – 9X = 18
Digits = X + Y = 10
on solving X = 4, Y = 6
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