A number when divided by 5 and 3 leaves remainders of 3 and 1, respectively. Find the smallest such 3 digit number.

Option 1 -

101

Option 2 -

103

Option 3 -

118

Option 4 -

None of these

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 2


    Detailed Solution:

    (b):Notice that the difference between the divisors and the remainder is constant. Therefore take the LCM of the divisors or any multiple of the LCM and subtract.

    The difference between the divisor and the remainder

    which is 2 in this case.

    Therefore, the smallest 3 digit number

    = 15 * 7? 2 = 105 – 2 = 103

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