An ellipse whose length of minor axis is equal to half of length between foci, then eccentricity is
An ellipse whose length of minor axis is equal to half of length between foci, then eccentricity is
Option 1 -
Option 2 -
Option 3 -
Option 4 -
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1 Answer
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Correct Option - 3
Detailed Solution:ae = 2b
Or 4 (1 – e2) = e2
4 = 5e2 ->
Similar Questions for you
If two circles intersect at two distinct points
->|r1 – r2| < C1C2 < r1 + r2
| r – 2| < < r + 2
|r – 2| < 5 and r + 2 > 5
–5 < r 2 < 5 r > 3 … (2)
–3 < r < 7 (1)
From (1) and (2)
3 < r < 7
x2 – y2 cosec2q = 5
x2 cosec2q + y2 = 5
and
->
1 + sin2q = 7 – 7 sin2q
->8sin2q = 6
->
->

Slope of axis =
⇒ 2y – 6 = x – 2
⇒ 2y – x – 4 = 0
2x + y – 6 = 0
4x + 2y – 12 = 0
α + 1.6 = 4 ⇒ α = 2.4
β + 2.8 = 6 ⇒ β = 3.2
Ellipse passes through (2.4, 3.2)
⇒
&
K
K =
48 = 16 (e2 – 1)
= 2 cos2 θ + 2 sin2 θ + 6 sin θ + 45
= 6 sin θ + 47
for maximum of PA2 + PB2, sin q = 1
then P (1, 2)
Hence P, A & B will lie on a straight line.
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