An online exam is attempted by 50 candidates out of which 20 are boys. The average marks obtained by boys is 12 with a variance 2. The variance of marks obtained by 30 girls is also 2. The average marks of all 50 candidates is 15. If μ is the average marks of girls and σ 2 is the variance of marks of 50 candidates, then μ + σ 2  is equal to____

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    Given variance of boys σ b 2 = 2 & x ¯ b = 1 2 (average marks of boys)

    & variance of girls  σ g 2 = 2 & μ average marks of girls

    N o w , x ¯ g = μ = 5 0 × 1 5 1 2 × 2 0 3 0 = 1 7           

    σ 2 = 2 0 × 2 + 3 0 × 2 2 0 + 3 0 + 2 0 × 3 0 ( 2 0 + 3 0 ) 2 ( 1 2 1 7 ) 2 = 8            

    S o , μ + σ 2 = 1 7 + 8 = 2 5  

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 687k Reviews
  • 1800k Answers

Learn more about...

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post