Answer the questions based on the following information.

Mr. John has 5 girls and 9 boys. He decides to give them a present on the occasion of Christmas. He takes 200 one-rupee coins and puts them in 2 bags which he closes. One of the bags contains more coins than the other. He asks his boys to choose one of the bags. They chose the bag with more money. When money is divided equally among boys they are left with Rs. 3. When money is divided equally among girls (not necessarily the same amount as given to boys), Rs. 4 was left. No girl gets less than a boy.

 

How many coins more did the bag, which the boys got, contain than the other?

Option 1 -

23

Option 2 -

40

Option 3 -

29

Option 4 -

Cannot be determined

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago
    Correct Option - 1


    Detailed Solution:

    9B + 3 + 5G + 4 = 200  9B + 5G = 193

    The positive integer solutions are (B, G) = (2, 35) (7, 25) (12, 17) (17, 8)

    Only one of the (B, G) gives G > B and 9B + 3 > 100, i.e. (B, G) = (12, 17)

     

    12 * 9 – 17 * 5 = 23

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