Forty eight litres of a solution contains rum and water in the ratio 5 : 3. How much quantity of water should be added so that the ratio of rum to water becomes 1 : 2?
Forty eight litres of a solution contains rum and water in the ratio 5 : 3. How much quantity of water should be added so that the ratio of rum to water becomes 1 : 2?
Option 1 -
12 litres
Option 2 -
30 litres
Option 3 -
42 litres
Option 4 -
24 litres
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1 Answer
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Correct Option - 3
Detailed Solution:(c) :As per the problem:
Initial amount of rum = 30 litres and water = 18 litres
New ratio of rum to water = 1 : 2
Therefore, if x is the amount of water to be added, then
18 + x = 60
x = 42 litres
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