From first 100 natural numbers, 3 numbers are selected. If these numbers are in A.P., then the probability that these numbers are even is:
From first 100 natural numbers, 3 numbers are selected. If these numbers are in A.P., then the probability that these numbers are even is:
Option 1 -
2/9
Option 2 -
29/56
Option 3 -
2/7
Option 4 -
24/49
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:A: 3 numbers are in A.P.
B: 3 numbers are even
P (B/A) = n (A ∩ B) / n (A) = (²? C? + ²? C? ) / (? C? +? C? ) = (25 × 24) / (50 × 49) = 12/49
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