How many numbers lying between 1000 and 2000 and divisible by 5 can be made with the digits 1, 2, 3, 5, 7 and 9? (Digits are not to be repeated in any number).
How many numbers lying between 1000 and 2000 and divisible by 5 can be made with the digits 1, 2, 3, 5, 7 and 9? (Digits are not to be repeated in any number).
Every number between 1000 and 2000, which is divisible by five and which can be formed by the given digits, must contains 5 in unit's place and 1 in thousand's place. Thus we are left with four digits out of which we are to place two between 1 and 5, which can be done in 4P2 = 12 ways. Hence, 12 nu
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xyz = 24
24 = 23 × 3
Let’s distribute 2, 3 among 3 variables. No. of positive integral solution =
No. of ways to distribute =
Rahul can occupy any one of the two corner positions and therefore, Rahul can occupy a position in two ways.
The other four people can seat themselves in 4! ways, that is, 24 ways.
Total ways = 2 * 24 = 48 ways.
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