(i) For any two complex numbers z1,z2 and any real numbers a,b , ? a 2 z 1 + b 2 z 2 ? ? b 2 z 1 + a 2 z 2 ? = . . . . .

(ii) The value of 25×9 is .....................

(iii) The number (1i)31i is equal to ...............

(iv) The sum of the series i+i2+i3+ up to 1000 terms is ..........

(v) Multiplicative inverse of 1+i is ................

(vi) If z1 and z2 are complex numbers such that z1+z2 is a real number, then z2=....

(vii)  (z)+z(z0) is ...............

(viii) If  ? z + 4 ? 3 , then the greatest and least values of ? z + 1 ? are ..... and .....

(ix) If z2z+6=π6, then the locus of z is ............

(x) If ? z ? = 4 and (z)=5π6 , then z=

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Similar Questions for you

A
alok kumar singh

  | 1 2 2 i + 1 | = α ( 1 2 2 i ) + β ( 1 + i )  

9 4 + 4 = α ( 1 2 2 i ) + β ( 1 + i )

5 2 = α ( 1 2 ) + β + i ( 2 α + β )             

α 2 + β = 5 2      ...(1)

 –2α + β = 0                    …(2)

Solving (1) and (2)

α 2 + 2 α = 5 2

5 2 α = 5 2            

a = 1

b = 2

-> a + b = 3

A
alok kumar singh

z 2 = i z ¯

| z 2 | = | i z ¯ |

| z 2 | = | z |

| z 2 | | z | = 0

| z | ( | z | 1 ) = 0

|z| = 0 (not acceptable)

|z| = 1

|z|2 = 1

A
alok kumar singh

Given : x2 – 70x + l = 0

->Let roots be a and b

->b = 70 – a

->= a (70 – a)

l is not divisible by 2 and 3

->a = 5, b = 65


-> 5 1 + 6 5 1 | 6 0 | = | 4 + 8 6 0 | = 1 5

A
alok kumar singh

z1 + z2 = 5

z 1 3 + z 2 3 = 2 0 + 1 5 i            

  z 1 3 + z 2 3 = ( z 1 + z 2 ) 3 3 z 1 z 2 ( z 1 + z 2 )           

z 1 3 + z 2 3 = 1 2 5 3 z 1 z 2 ( 5 )            

 ⇒ 20 + 15i = 125 – 15z1z2

3z1z2 = 25 – 4 – 3i

3z1z2 = 21– 3i

z1z2 = 7 – i

(z1 + z2)2 = 25

z 1 2 + z 2 2 = 2 5 2 7 ( 7 i )     

= 11 + 2i

  ( z ? 1 2 + z 2 2 ) 2         = 121 − 4 + 44i

  z 1 4 + z 2 4 + 2 ( 7 i ) 2 = 1 1 7 + 4 4 i

  z 1 4 + z 2 4 = 117 + 44i − 2(49 −1−14i )

= 21 + 72i

  | Z 1 4 + Z 2 4 | = 7 5

V
Vishal Baghel

x 2 2 ( 3 k 1 ) x + 8 k 2 7 > 0 a > 0 , & D < 0 ,

a = 1 > 0 and D < 0

4 (3k – 1)2 – 4 (8k2 – 7) < 0

  ( 9 k 2 + 1 6 k 8 k 2 + 7 < 0 )

k ( k 4 ) 2 ( k 4 ) < 0

k ( 2 , 4 )

K = 3

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