If a point A(x, y) lies in the region bounded by the y-axis, straight lines 2y + x = 6 and 5x – 6y = 30, then the probability that y < 1 is

Correct Option - 2


Detailed Solution:

The required probability

$=\frac{AreaofRegionPQCAP}{AreaofRegionABCA}$

$=\frac{\frac{1}{2}\times 8\times 6-\frac{1}{2}\times 2\times 4}{\frac{1}{2}\times 8\times 6}$

$=\frac{5}{6}$

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