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If the foot of the perpendicular drawn from the origin to a plane is (5, –3, –2), then the equation of the plane is r → ⋅ ( 5 i ^ − 3 j ^ + 2 k ^ ) − 3 8 .     

0 3 Views | Posted 3 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    This is a True or False Type Questions as classified in NCERT Exemplar

    T h e     g i v e n     e q u a t i o n     o f     t h e     p l a n e     i s       r → . ( 5 i ^ − 3 j ^ − 2 k ^ ) = 3 8 I f     t h e     f o o t     o f     t h e     p e r p e n d i c u l a r     t o     t h i s     p l a n e     i s                       ( 5 ,   − 3 ,   − 2 )     i . e . ,     5 i ^ − 3 j ^ − 2 k ^     t h e n ⇒                 ( 5 i ^ − 3 j ^ − 2 k ^ ) . ( 5 i ^ − 3 j ^ − 2 k ^ ) = 3 8 ⇒                                                                                                       2 5 + 9 + 4 = 3 8                                                                                 3 8 = 3 8 ( s a t i s f i e d ) H e n c e ,     t h e     g i v e n     s t a t e m e n t     i s     T r u e .

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