If the system of equations αx + y + z = 5, x + 2y + 3Z = 4, x + 3y + 5z = β has infinitely many solutions, then the ordered pair (α, β) is equal to:
If the system of equations αx + y + z = 5, x + 2y + 3Z = 4, x + 3y + 5z = β has infinitely many solutions, then the ordered pair (α, β) is equal to:
Option 1 -
(1, -3)
Option 2 -
(-1, 3)
Option 3 -
(1, 3)
Option 4 -
(-1, -3)
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:Given system of equations
αx + y + z = 5
x + 2y + 3z = 4, has infinite solution
x + 3y + 5z =β
= 0
α (1) – 1 (2) + 1 (1) = 0
α= 1 and
β= 3
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