If y = y(x) is the solution of the differential equation (5+e?)/(2+y) dy/dx + e? = 0 satisfying y(0) = 1, then a value of y(log? 13) is:
If y = y(x) is the solution of the differential equation (5+e?)/(2+y) dy/dx + e? = 0 satisfying y(0) = 1, then a value of y(log? 13) is:
Option 1 -
0
Option 2 -
1
Option 3 -
-1
Option 4 -
2
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:R (-1+2r, 3-2r, -r)
dr's of PR are (2 - 2r, -1+2r, -3+r)
Then 2 (2-2r) + 2 (-1+2r) + 1 (3-r) = 0
9-9r = 0 ⇒ r = 1
R (1,1, -1)
then a+1=2, b+2=2, c-3=-2
a=1, b=0, c=1
∴ a+b+c = 2
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