In a quiz, six team with two member one man and one woman each participated. During dinner all the 12 members were seated around a round table. Find the probability that no man sat to the left of the woman from this team, provided that men and women were alternatively seated.   

Option 1 -

23/108

Option 2 -

23/1008

Option 3 -

53/144

Option 4 -

53/1444

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:

    Total numbers of ways = 5 × 6

    Numbers of ways in which men can sit such that no men sat to the left of the women from his team i.e. Derangement of 6

    D6 = 6! [10! +11! +12! +13! +16! ]

    = 265

    F (0) = 5 × 265

    Probability = 5!×2656!×5!=53144

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