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In the figure given below, ABCD is a rectangle. The area of the isosceles right triangle ABE = 7 cm2; EC = 3(BE). The area of ABCD (in cm2) is

Option 1 -

21 cm2

Option 2 -

28 cm2

Option 3 -

42 cm2

Option 4 -

56 cm2

0 13 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Area of Δ ABE = 7 cm2

    Area of ABEF = 14 cm2

    Area of ABCD = 14 × 4 = 56 cm2

    (As CE = 3 × BE) = 56 cm2

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