Let 1 – log10105 = 1/3(log10101/2 + log1010x + 1/3log10105) Where x = 2m/5n, then what is the value of m + 3n?
Let 1 – log10105 = 1/3(log10101/2 + log1010x + 1/3log10105) Where x = 2m/5n, then what is the value of m + 3n?
Option 1 -
5
Option 2 -
6
Option 3 -
9
Option 4 -
13/3
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:3 [log101010 – log10105] =
log101023 =
23 =
x =
Hence, m + 3n = = 5
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