Let A = [[-i, 1], [-i, i]], i = √-1. Then, the system of linear equation A?[x; y] = [8; 64] has :
Let A = [[-i, 1], [-i, i]], i = √-1. Then, the system of linear equation A?[x; y] = [8; 64] has :
Option 1 -
Infinitely many solutions
Option 2 -
No solution
Option 3 -
Exactly two solutions
Option 4 -
A unique solution
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:A = [i, -i], [-i, i]
A² = [-2, 2], [2, -2]
A? = [8, -8], [-8, 8]
A? = [-128, 128], [128, -128]
A? [x, y]? =?
-128x + 128y = 8 ⇒ -16x + 16y = 1 ⇒ x - y = -1/16 (I)
128x - 128y = 64 ⇒ 16x - 16y = 8 ⇒ x - y = 1/2 (II)
System is inconsistent hence No solution
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