Let a vertical tower AB of height 2h stands on a horizontal ground. Let from a point P on the ground a man can see upto height h of the tower with an angle of elevation 2a. When from P, he moves a distance d in the direction of $\overrightarrow{AP}$ , he can see the top B of the tower with an angle of elevation a. If d =   $\sqrt[]{7}h,$ then tan a is equal to

Correct Option - 3


Detailed Solution:

Solve tan 2a = $\frac{h}{b}$  

$tan\alpha =\frac{2h}{\sqrt[]{7}h+b}$

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