Let f:R→R be defined as f(x)={x⁵sin(1/x)+5x², x<0; 0, x=0; x⁵cos(1/x)+λx², x>0}. The value of λ for which f"(0) exists, is [numerical value].
Let f:R→R be defined as f(x)={x⁵sin(1/x)+5x², x<0; 0, x=0; x⁵cos(1/x)+λx², x>0}. The value of λ for which f"(0) exists, is [numerical value].
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1 Answer
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f" (0)=10, f" (0+)=2λ. λ=5.
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