Let f(x) = x - [x/2] for -10 < x < 10, where [t] denotes the greatest integer function. Then the number of points of discontinuity of f is equal to
Let f(x) = x - [x/2] for -10 < x < 10, where [t] denotes the greatest integer function. Then the number of points of discontinuity of f is equal to
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1 Answer
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-5 ≤ [x/2] < 5
I ⇒ [x/2] = -5, -4, -3, -2, -1,0,1,2,3,4
Hence, function is discontinues at = -4, -3, -2, -1,1,2,3,4 Number of values is 8.
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