Let n be a non-negative integer. Then the number of divisors of the form “4n+1” of the number (10)¹⁰ . (11)¹¹ . (13)¹³ is equal to………..
Let n be a non-negative integer. Then the number of divisors of the form “4n+1” of the number (10)¹⁰ . (11)¹¹ . (13)¹³ is equal to………..
Asked by Shiksha User
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1 Answer
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N=2¹? 5¹? 11¹¹ 13¹¹
5→4n+1 type→number of choice=11
11→4n+3 type→number of choice=6
13→4n+1 type→number of choice=12
. Number of divisor of 4n+1 type=11×6×12=792
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