Let P(3,3) be a point on the hyperbola, x2a2-y2b2=1 . If the normal to it at P intersects the x -axis at (9,0) and e is its eccentricity, then the ordered pair a2,e2 is equal to:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mfenced separators="|"> <mrow> <mrow> <mfrac> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <mo>,</mo> <mn>2</mn> </mrow> </mrow> </mfenced> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mfenced separators="|"> <mrow> <mrow> <mfrac> <mrow> <mrow> <mn>9</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <mo>,</mo> <mn>2</mn> </mrow> </mrow> </mfenced> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mo>(</mo> <mn>9,3</mn> <mo>)</mo> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mfenced separators="|"> <mrow> <mrow> <mfrac> <mrow> <mrow> <mn>9</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <mo>,</mo> <mn>3</mn> </mrow> </mrow> </mfenced> </math> </span></p>
4 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
7 months ago
Correct Option - 4
Detailed Solution:

Since  (3,3) lies on x2a2-y2b2=1

9a2-9b2=1

Now, normal at  (3,3) is y-3=-a2b2 (x-3) ,

which passes through  (9,0)b2=2a2

So,  e2=1+b2a2=3

Also,  a2=92

(From (i) and (ii)

Thus,  a2, e2=92, 3

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Maths NCERT Exemplar Solutions Class 12th Chapter Eleven 2025

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