Let p and q be the roots of the equation x² – 4ax + 3 = 0. If $\left(\frac{2}{p}-q\right)and\left(\frac{2}{q}-p\right)$ are the roots of the equation x2 – 2bx + c = 0 then what is the value of ‘c’?

<p>p and q are the roots of the equation x² – 4ax + 3 = 0</p><p>pq = 3</p><p>Similarly the constant term of x² – 2bx + c = 0</p><p>Product of&nbsp;<math><mrow><mrow><mo> (</mo><mrow><mfrac><mrow><mn>2</mn></mrow><mrow><mi>p</mi></mrow></mfrac><mo>−</mo><mi>q</mi></mrow><mo>)</mo></mrow><mi>a</mi><mi>n</mi><mi>d</mi><mrow><mo> (</mo><mrow><mfrac><mrow><mn>2</mn></mrow><mrow><mi>q</mi></mrow></mfrac><mo>−</mo><mi>p</mi></mrow><mo>)</mo></mrow></mrow></math></p><p>Hence, c =&nbsp;<math><mrow><mfrac><mrow><mn>4</mn></mrow><mrow><mi>p</mi><mi>q</mi></mrow></mfrac><mo>−</mo><mn>2</mn><mo>−</mo><mn>2</mn><mo>+</mo><mi>p</mi><mi>q</mi><mo>=</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>3</mn></mrow></mfrac></mrow></math></p>

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