Let the tangents drawn from the origin to the circle, $x^2+y^2-8x-4y+16=0$ touch it at the points $A$ and $B$ . Then $(AB{)}^2$  is equal to:

Correct Option - 3


Detailed Solution:

OS = √S?
Radius = R = 2
Length of AB = (2RL)/√(L²+R²) = 16/√20
AB² = 64/5

 

<p>OS = √S?<br>Radius = R = 2<br>Length of AB = (2RL)/√(L²+R²) = 16/√20<br>AB² = 64/5</p><div><div><picture><source srcset="" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1755859735phpYcQd0r.jpeg" alt="" width="437" height="194" loading="lazy"></picture></div></div><p>&nbsp;</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment