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lim?→? [x² + 1] + [x² - 1] + {x} [Here [ . ] is GIF and { . } is Fractional part function]

Option 1 -

127

Option 2 -

160

Option 3 -

161

Option 4 -

162

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago
    Correct Option - 3


    Detailed Solution:

    l i m x → 9 - ? x 2 + 1 + x 2 - 1 + { x }

    ⇒ l i m x → 9 - ? 2 x 2 + { x } ⇒ l i m h → 0 ? 2 ( 9 - x ) 2 + { 9 - h } = 160 + 1 = 161

Similar Questions for you

If [t] denotes the greatest integer ≤t, then the value of ∫01[2x−|3x2−5x+2|+1]dx  is:
P
Payal Gupta

y = 2x |3x2−5x+2|,0≤x≤1

={−3x2+7x−2,3x2−3x+2,0≤x≤2323<x≤1

3x2 – 5x + 2 = 0

x=+5±25−246

= 5+16=1,23

3x2 – 7x + 3 = 0

x = 7±49−396=7±136

−3x2+7x−2

−7±49−24−6=7+56=2,13

3x2 + 7x – 2 = 1

3x2 – 7x + 1 = 0

x = 7±49−126=7±376

I = ∫06((−2)+1)dx+∫7−37613((−1)+1)dx+∫−137−136(0+1)dx+∫7−13623(1+1)dx+∫231(1+1)dx

=37+13−46

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