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Solution of the differential equation, xdy = x y     d x 1 − x 2 − y d x is (where s ∈  (-1, 1))

Option 1 -

loge | x y |  = sin-1x + C       

Option 2 -

loge | x y |  = 2sin-1x + C

Option 3 -

loge | ( x + y ) |  = 2sin-1x + C

Option 4 -

loge | ( x + y ) | = 2 s i n − 1 x + C

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago
    Correct Option - 1


    Detailed Solution:

    x   d y + y   d x = x y   d x 1 − x 2

    d ( x y ) x y = d x 1 − x 2

    Integrate both sides we get

    logexy = sin1 x + C

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