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The equation of the straight line passing through the point (3, 2) and perpendicular to the line y=x is

(a)   X-y=5

(b)  X+y=5

(c)   X+y=1

(d)  X-y=1

0 4 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Objective Type Questions as classified in NCERT Exemplar

    Sol:

    Equation  of  line  'l'  is  given  by          y−y1=m(x−x1)  l  is    through  the    P(3,2).∴        y−2=m(x−3)⇒             y=mx+2−3m                                       …(i)  it  is  given  that  lines  y=x  and  'l'  are  perpendicular  to  each  other,∴        m×1=−1            [?m1×m2=−1]                m=−1Put  m=−1  in  eqn.(i),  we  get          y=−x+2−3(−1)          y=−x+5  x+y=5Hence,  the  correct  option  is  (b).

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