The number of 5-digit natural numbers, such that the product of their digits is 36, is……
The number of 5-digit natural numbers, such that the product of their digits is 36, is……
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1 Answer
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Factors of 36 = 22.32.1
Five-digit combinations can be
(1, 2, 3, 3), (1, 4, 3, 1), (1, 9, 2, 1), (1, 4, 9, 11), (1, 2, 3, 6, 1), (1, 6, 1, 1)
i.e., total numbers
Similar Questions for you
Start with
(1)
(2)
(3) GTE : 4!, GTN: 4!, GTT : 4!
(4) GTWENTY = 1
⇒ 360 + 60 + 60 + 24 + 24 + 24 + 1 = 553
x + 2y + 3z = 42
0 x + 2y = 42 ->22 cases
1 x + 2y = 39 ->19 cases
2 x + 2y = 36 ->19 cases
3 x + 2y = 33 ->17 cases
4 x + 2y = 30 ->16 cases
5 x + 2y = 27 ->14 cases
6 x + 2y = 24 ->13 cases
7 x + 2y = 21 ->11 cases
8 x + 2y = 18 ->10 cases
9 x + 2y = 15 ->8 cases
10 x + 2y =12 -> 7 cases
11 x + 2y = 9 -> 5 cases
12 x + 2y = 6 -> 4 cases
13 x + 2y = 3 -> 2 cases
14 x + 2y = 0 -> 1 cases.
Total ways to partition 5 into 4 parts are:
5 0
4 1 0
3 2 0
3 1 0
2 1
51 Total way
After giving 2 apples to each child 15 apples left now 15 apples can be distributed in
15+3–1C2 = 17C2 ways
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