The number of natural numbers lying between 1012 and 23421 that can be formed using the digits 2, 3, 4, 5, 6 (repetition of digits is not allowed) and divisible by 55 is…………
The number of natural numbers lying between 1012 and 23421 that can be formed using the digits 2, 3, 4, 5, 6 (repetition of digits is not allowed) and divisible by 55 is…………
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1 Answer
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1012 Number in the question 23421
Also, the number has to use digits {2, 3, 4, 5, 6} without repetition and the number has to be divisible by
As the number has to be divisible by both 5 and 11,
5->once place
Let us make 4-digit such numbers first:
{2, 3, 4, 6} (digits are not be repeated)
A number is divisible by 11 it difference of sum of its digits at even places and sum of digits at odd place is 0 or multiple of 11.
->Total 6 numbers 3245, 4235, 6325, 2365, 3465, 6435
Let us make 5 digit such numbers
2 4 &nb
...more
Similar Questions for you
Start with
(1)
(2)
(3) GTE : 4!, GTN: 4!, GTT : 4!
(4) GTWENTY = 1
⇒ 360 + 60 + 60 + 24 + 24 + 24 + 1 = 553
x + 2y + 3z = 42
0 x + 2y = 42 ->22 cases
1 x + 2y = 39 ->19 cases
2 x + 2y = 36 ->19 cases
3 x + 2y = 33 ->17 cases
4 x + 2y = 30 ->16 cases
5 x + 2y = 27 ->14 cases
6 x + 2y = 24 ->13 cases
7 x + 2y = 21 ->11 cases
8 x + 2y = 18 ->10 cases
9 x + 2y = 15 ->8 cases
10 x + 2y =12 -> 7 cases
11 x + 2y = 9 -> 5 cases
12 x + 2y = 6 -> 4 cases
13 x + 2y = 3 -> 2 cases
14 x + 2y = 0 -> 1 cases.
Total ways to partition 5 into 4 parts are:
5 0
4 1 0
3 2 0
3 1 0
2 1
51 Total way
After giving 2 apples to each child 15 apples left now 15 apples can be distributed in
15+3–1C2 = 17C2 ways
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