The sum of the absolute minimum and the absolute maximum values of the friction f(x) =
in the interval [-1, 2] is:
The sum of the absolute minimum and the absolute maximum values of the friction f(x) = in the interval [-1, 2] is:
Option 1 -
Option 2 -
Option 3 -
5
Option 4 -
-
1 Answer
-
Correct Option - 1
Detailed Solution:absolute minimum
absolute maximum = 3
Similar Questions for you
option (C) is incorrect, there will be minima.
If f(x) has maximum value at x = 1 then
……..(i)
……..(ii)
From (i) and (ii) we get
OP2 = x2 = y2
y = ex, y’ = ex,
slope of normal =
By hit and trial we get
c = -5, a = 2, b = 1
CD = √ (10+x²)² – (10–x²)² = 2√10|x|
Area
= 1/2 × CD × AB = 1/2 × 2√10|x| (20–2x²)
=> 10 – x² = 2x
3x² = 10
x = k
3k² = 10
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