The term independent of 'x' in the expression of [(x+1)/(x²/³ - x¹/³ + 1) - (x-1)/(x-x¹/²)]¹?, where x ≠ 0, 1 is equal to…….
The term independent of 'x' in the expression of [(x+1)/(x²/³ - x¹/³ + 1) - (x-1)/(x-x¹/²)]¹?, where x ≠ 0, 1 is equal to…….
Asked by Shiksha User
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1 Answer
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(x+1)/ (x²/³-x¹/³+1) - (x-1)/ (x-x¹/²) = (x¹/³+1) - (1+x? ¹/²)
= (x¹/³ - x? ¹/²)¹?
general term = ¹? C? (x¹/³)¹? (-x? ¹/²)? = ¹? C? x^ (20-5r)/6)
For independent of x, 20-5r=0 ⇒ r=4
∴ Coefficient = ¹? C? = 210
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