There are ten boys B₁, B₂,….., B₁₀ and five girls G₁, G₂,….., G₅ in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B₁ and B₂ together should not be the members of a group, is………….

Boys (10)            Girls (5)

(3)                        (3)

B₁ & B₂ should not be selected together

Total number of ways

           

= (56 + 56) × 10 = 1120

<p>Boys (10)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Girls (5)</p><p> (3)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (3)</p><p>B₁ &amp; B₂ should not be selected together</p><p>Total number of ways</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1753091633php4at6yM.jpeg" alt="" width="142" height="37" loading="lazy"></picture>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1814617006"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;</div></div><p>= (56 + 56) × 10 = 1120</p>

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