Two equal containers are filled with a mixture of 2 metals Gold and Platinum. First contains 3 times as much metal Gold as the second. The mixture in the two containers are then mixed and it is found that the ratio becomes 2 : 5. Find the original ratio of Gold : Platinum in the first container.
Two equal containers are filled with a mixture of 2 metals Gold and Platinum. First contains 3 times as much metal Gold as the second. The mixture in the two containers are then mixed and it is found that the ratio becomes 2 : 5. Find the original ratio of Gold : Platinum in the first container.
Option 1 -
3 : 4
Option 2 -
2 : 3
Option 3 -
5 : 3
Option 4 -
6 : 5
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1 Answer
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Correct Option - 1
Detailed Solution:Let X = Total Amount of Gold
& Y = Total Amount of Platinum
. (1)
Given U1 + P1 = U2 + P2. (2)
U1 + U1 = X & P1 + P2 = Y. (3)
Also, given U1 = 3U2
From (2) P2 − P1 = 2U2
Also, X = 4U2 & 2P1 = Y − 2U2
4P1 + 4U2 = 20U2
4P1 = 16U2
U1 : P1 = 3 : 4
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