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What is the least number which, when divided by 5, 6, 7, 8 gives remainder 3 in each case but is divisible by 11?

Option 1 -

1263

Option 2 -

1677

Option 3 -

1683

Option 4 -

3663

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago
    Correct Option - 3


    Detailed Solution:

    L.C.M. of 5, 6, 7, 8

    = 35 * 24 = 840

    Therefore, the required number = 840x + 3,

    Which is exactly divisible by 11.

    For x = 2, it is divisible by 11.

    Hence,

    Required number = 840x + 3

    = 840 * 2 + 3

    = 1683

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