While calculating the mean and variance of 10 readings, a student wrongly used the reading 52 for the correct reading 25. He obtained the mean and variance as 45 and 16, respectively. Find the correct mean and variance.

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    Payal Gupta | Contributor-Level 10

    2 months ago

    This is a long answer type question as classified in NCERT Exemplar

    G i v e n t h a t n = 1 0 , x ¯ = 4 5 , σ 2 = 1 6 x ¯ = x i n 4 5 = x i 1 0 x i = 4 5 0 C o r r e c t e d x i = 4 5 0 5 2 + 2 5 = 4 2 3 a n d C o r r e c t e d m e a n = 4 2 3 1 0 = 4 2 . 3 N o w σ 2 = x i 2 n ( x i n ) 2 1 6 = x i 2 1 0 ( 4 5 ) 2 1 6 = x i 2 1 0 2 0 2 5 x i 2 1 0 = 2 0 4 1 x i 2 = 2 0 4 1 × 1 0 x i 2 = 2 0 4 1 0 C o r r e c t e d x i 2 = 2 0 4 1 0 ( 5 2 ) 2 + ( 2 5 ) 2 = 2 0 4 1 0 2 7 0 4 + 6 2 5 = 1 8 3 3 1 a n d C o r r e c t e d v a r i a n c e σ 2 = 1 8 3 3 1 1 0 ( 4 2 . 3 ) 2 = 1 8 3 3 . 1 1 7 8 9 . 3 = 4 3 . 8 H e n c e , t h e r e q u i r e d m e a n = 4 2 . 3 a n d v a r i a n c e = 4 3 . 8

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