1.15 Consider a uniform electric field E = 3 ×103 î N/C.

(a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?

(b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

0 79 Views | Posted 3 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    1.15 (a) Electric field intensity, E = 3 ×103 î N/C

    Magnitude of electric field intensity, E=3×103 = 
     N/C

    Side of the square, s = 10 cm = 0.1 m

    Area of the square, A = s2 = 0.01 m2

    The plane of the square is parallel to the y-z plane, hence the angle between the unit vector normal to the plane and electric field, θ= 0 °

    Flux ( φ) through the plane is given by the relation,  φ = EAcos?θ3×103×0.01×cos?0°=30
    Nm2/C

    (b) When the normal to its plane make a 60 ° angle with x-axis,θ  = 60 
     . From the equation φ =EAcos?θwe get  = φ 3×103×0.01×cos?60°=15 Nm2/C

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