1.22 A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/ .
(a) Find the charge on the sphere.
(b) What is the total electric flux leaving the surface of the sphere?
1.22 A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/ .
(a) Find the charge on the sphere.
(b) What is the total electric flux leaving the surface of the sphere?
-
1 Answer
-
1.22
(a) Diameter of the sphere, d = 2.4 m, Radius, r = 1.2 m
Surface charge density, = 80 μC/
= 80m 2 C/× 10 - 6 m 2 Total charge on the surface of the sphere is given by Q =
A, where A = surface area of the sphere = 4σ π r 2 Hence Q = 80
C = 1.447× 10 - 6 × 4 × π × 1.2 2 C× 10 - 3 (b) The total electric flux (
) is given byφ T o t a l =φ T o t a l Q ? 0 , where
= Permittivity of free space = 8.854? 0 × 10 - 12 C 2 N - 1 ,m - 2 Q = 1.447
C× 10 - 3 =φ T o t a l
1.447 × 10 - 3 8.854 × 10 - 12 C - 1 N = 1.63m 2 × 10 8 C - 1 N m 2
Similar Questions for you
The following are the topics covered in this chapter: Electric Field and Field Lines, Gauss's Law, Electric Dipole, Conductors and Insulators, and Electric Flux.
Indeed, it is an easy chapter of Class 12 Physics. In this chapter, you will learn about the foundational concepts like Gauss's law and electric fields.
Flux through the 6 sides of square (i.e. cube)
Flux through a square
In the medical entrance test NEET, this chapter has a moderate weightage. You can expect around 2-3 questions of this chapter that contributes to the 3-5% of the total marks in the Physics section.
From Guass’s Law
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers