1.24 Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0  $\times {10}^{-22}\mathit{}$ C/${\mathit{m}}^2$. What is E:

(a) In the outer region of the first plate

(b) In the outer region of the second plate

(c) Between the plates?

1.24 The given conditions are explained in the adjacent diagram

 

Where A and B represent two large, thin metal plates, parallel and close to each other. The outer surface of A is shown as I, outer surface of B is shown as II and the surface in between A and B is shown as III.

Charge density of plate A, $\sigma$ = 17.0 $\times {10}^{-22}$C/$m^2$

Charge density of plate B, $\sigma$ = $-$ 17.0 $\times {10}^{-22}$
 C/ $m^2$$$

(a) & (b) In the region, I and III, electric field E is zero, because charge is not enclosed by the respective plates.

 

(c) Electric field, E in the region II is given by

E = $\frac{\sigma }{{?}_0}$
 , where

${?}_0$ = Permittivity of free space = 8.854  $\times {10}^{-12}$ $C^2{N}^{-1}$$m^{-2}$

E = $\frac{17.0\mathrm{}\times {10}^{-22}}{8.854\mathrm{}\times {10}^{-12}}$ N/C = 1.92$\times {10}^{-10}$  N/C

...more

1.24 The given conditions are explained in the adjacent diagram

 

Where A and B represent two large, thin metal plates, parallel and close to each other. The outer surface of A is shown as I, outer surface of B is shown as II and the surface in between A and B is shown as III.

Charge density of plate A, $\sigma$ = 17.0 $\times {10}^{-22}$C/$m^2$

Charge density of plate B, $\sigma$ = $-$ 17.0 $\times {10}^{-22}$
 C/ $m^2$$$

(a) & (b) In the region, I and III, electric field E is zero, because charge is not enclosed by the respective plates.

 

(c) Electric field, E in the region II is given by

E = $\frac{\sigma }{{?}_0}$
 , where

${?}_0$ = Permittivity of free space = 8.854  $\times {10}^{-12}$ $C^2{N}^{-1}$$m^{-2}$

E = $\frac{17.0\mathrm{}\times {10}^{-22}}{8.854\mathrm{}\times {10}^{-12}}$ N/C = 1.92$\times {10}^{-10}$  N/C

less

<p><strong>1.24 </strong>The given conditions are explained in the adjacent diagram</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1728896368php6v5WsH_480x360.jpeg" media="(max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1728896368php6v5WsH.jpeg" alt="" width="221" height="98"></picture></div></div><p>&nbsp;</p><p>Where A and B represent two large, thin metal plates, parallel and close to each other. The outer surface of A is shown as I, outer surface of B is shown as II and the surface in between A and B is shown as III.</p><p>Charge density of plate A, <span title="Click to copy mathml"><math><mi>σ</mi></math></span> = 17.0 <span title="Click to copy mathml"><math><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>22</mn></mrow></mrow></msup><mi></mi></math></span>C/<span title="Click to copy mathml"><math><msup><mrow><mrow><mi>m</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup></math></span></p><p>Charge density of plate B, <span title="Click to copy mathml"><math><mi>σ</mi></math></span> = <span title="Click to copy mathml"><math><mo>-</mo></math></span>&nbsp;17.0 <span title="Click to copy mathml"><math><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>22</mn></mrow></mrow></msup></math></span><span title="Click to copy mathml"><br></span>&nbsp;C/ <span title="Click to copy mathml"><math><msup><mrow><mrow><mi>m</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup></math></span><math><mi></mi></math></p><p><strong>(a) </strong>&amp;<strong> (b)</strong> In the region, I and III, electric field E is zero, because charge is not enclosed by the respective plates.</p><p>&nbsp;</p><p><strong>(c)</strong> Electric field, E in the region II is given by</p><p>E = <span title="Click to copy mathml"><math><mfrac><mrow><mrow><mi>σ</mi></mrow></mrow><mrow><mrow><msub><mrow><mrow><mi>?</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub></mrow></mrow></mfrac></math></span><span title="Click to copy mathml"><br></span>&nbsp;, where</p><p><span title="Click to copy mathml"><br></span><span title="Click to copy mathml"><math><msub><mrow><mrow><mi>?</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub></math></span> = Permittivity of free space = 8.854&nbsp;&nbsp;<span title="Click to copy mathml"><math><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>12</mn></mrow></mrow></msup></math></span>&nbsp;<span title="Click to copy mathml"><math><msup><mrow><mrow><mi>C</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><msup><mrow><mrow><mi>N</mi></mrow></mrow><mrow><mrow><mo>-</mo><mn>1</mn></mrow></mrow></msup></math></span><span title="Click to copy mathml"><math><msup><mrow><mrow><mi>m</mi></mrow></mrow><mrow><mrow><mo>-</mo><mn>2</mn></mrow></mrow></msup></math></span></p><p>E = <span title="Click to copy mathml"><math><mfrac><mrow><mrow><mn>17.0</mn><mi mathvariant="normal"></mi><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>22</mn></mrow></mrow></msup></mrow></mrow><mrow><mrow><mn>8.854</mn><mi mathvariant="normal"></mi><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>12</mn></mrow></mrow></msup></mrow></mrow></mfrac></math></span>&nbsp;N/C = 1.92<span title="Click to copy mathml"><math><mo>×</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>10</mn></mrow></mrow></msup></math></span> &nbsp;N/C</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment