1.28 (a) A conductor A with a cavity as shown in Fig. 1.36(a) is given a charge Q. Show that the entire charge must appear on the outer surface of the conductor.

 

(b) Another conductor B with charge q is inserted into the cavity keeping B insulated from A. Show that the total charge on the outside surface of A is Q + q [Fig. 1.36(b)].

 

(c) A sensitive instrument is to be shielded from the strong electrostatic fields in its environment. Suggest a possible way.

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    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    1.28 (a) Let us consider a Gaussian surface that is lying wholly within a conductor and enclosing the cavity. The electric field intensity E inside the charged conductor is zero.

    Let q be the charge inside the conductor and ?0 the permittivity of free space.

    According to Gauss’s law, Flux,φ  = E.ds = q?0

    Here, E = 0, hence q?0 = 0, so q = 0 (as ?00)

    Therefore, the charge inside the conductor is zero. The entire charge Q appears on the outer surface of the conductor.

     

    (b) The outer surface of the conductor A has a charge amount Q. Another conductor B, having charge +q is kept inside conductor A and it is insulated from A. Hence,

    ...more

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