12.8 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.8 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
-
1 Answer
-
12.8 The radius of the innermost orbit of a hydrogen atom, = 5.3 m
Let be the radius of the orbit at n = 2. The relation between the radius of the orbit is
= =4 =21.2
Let be the radius of the orbit at n = 3. The relation between the radius of the orbit is
= =9 =47.7
Similar Questions for you
Kindly go through the solution
Change in surface energy = work done
|DE0| = –10.2

]
= 3 m/s
n = 4
Number of transitions =
Kinetic energy: Potential energy = 1 : –2
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 680k Reviews
- 1800k Answers

