15.18 Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?

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    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    Frequency of string A, fA = 324 Hz, let the frequency of string B, be = fB

    Beat’s frequency, n = 6 Hz

    Beat’s frequency is given as n = fA±fB or 6 = 324 ±fB

    fB=318Hzor330Hz

    Frequency decreases with a decrease in the tension in a string. This is because frequency is directly proportional to the square root of tension, . It is given as

    νT

    Hence the beat frequency cannot be 330 Hz. So fB=318Hz

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