15.18 Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?
15.18 Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?
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1 Answer
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Frequency of string A, = 324 Hz, let the frequency of string B, be =
Beat’s frequency, n = 6 Hz
Beat’s frequency is given as n = or 6 = 324
Frequency decreases with a decrease in the tension in a string. This is because frequency is directly proportional to the square root of tension, . It is given as
Hence the beat frequency cannot be 330 Hz. So
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