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15.2 A stone dropped from the top of a tower of height 300 m splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s–1? (g = 9.8 m s–2)

0 6 Views | Posted 5 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    5 months ago

    Height of the tower, h = 300 m

    Initial velocity of the stone, u = 0

    Acceleration, a = g = 9.8 m/ s2

    Speed of sound in air, V = 340 m/s

    The time taken by the stone (t), to strike the water can be calculated from the relation

    s =us + 12 a t2 as

    300 = 0 + 12*9.8*t2 or t = 7.82 s

    Time taken by the sound to reach the top of the tower,  t1 = hV = 300340 = 0.88 s

    Therefore, the time when the splash can be heard = 7.82 + 0.88 = 8.7 s

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