2.9 Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
2.9 Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
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1 Answer
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2.9 Dielectric constant of the mica sheet, k =6
While the voltage supply remained connected :
V = 100 V
Initial capacitance, C = 17.708 F
New capacitance, = kC = 6 17.708 = 106.25 F
= 106.25 pF
New charge, = = 106.25 C = 10.62 C
If the supply voltage is removed, then there will be constant amount of charge in the plates.
Charge, q = CV = 17.708 C = 1.7708 C
Potential across plates, = = = 16.66 V
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