27 similar drops of mercury are maintained at 10V each. All these spherical drops combine into a single big drop. The potential energy of the bigger drop is……… times that of a smaller drop.

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6 months ago

With the help of conservation of volume, we can write

27*43πr3=43πR3R=3r....... (1)

With the help of conservation of charge, we can write

Q = 27 q. (2)

Potential energy of single drop = U1 = q28πε0r

Potential energy of bigger drop = U2=Q28πε0R=27*27*q28πε0 (3r)=243 (q28πε0r)=243U1

U2U1=243

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physics ncert exemplar solutions class 12th chapter two 2025

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