3.10 (a) In a meter bridge [Fig. 3.27], the balance point is found to be at 39.5 cm from the end A, when the resistor S is of 12.5 Ω. Determine the resistance of R. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?

(b) Determine the balance point of the bridge above if R and S are interchanged.

(c) What happens if the galvanometer and cell are interchanged at the balance point of the bridge? Would the galvanometer show any current?

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    Answered by

    Payal Gupta | Contributor-Level 10

    5 months ago

    3.10 (a) Balance point from end A, l1 = 39.5 cm

    Resistance of the resistor, S = 12.5 Ω

    Condition for the balance is given as,

    RS = l1100-l1

    R=S×l1100-l1 = 12.5 ×39.5100-39.5 = 8.16 Ω

    Theconnectionbetween resistorsinaWheatstone bridge is made of thick copper strips to minimize the resistance, which is not taken into consideration in the bridge formula.

    (b) If R & S are interchanged, then l1 and (100 - l1 ) will also get interchanged. The balance point will be (100- l1) from A. So the new balance point is 100 – 39.5 = 60.5 cm from A.

    (c) When the galvanometer and cell are interchanged at the balance point of the bridge, the galvanometer will s

    ...more

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