3.13 The number density of free electrons in a copper conductor estimated in Example 3.1 is 8.5 * 1028 m–3. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? The area of cross-section of the wire is 2.0 * 10–6 m2 and it is carrying a current of 3.0 A.

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8 months ago

3.13 Given, number of free electron in a copper conductor, n = 8.5 *1028 m-3

Length of the copper wire, l = 3.0 m

The area of cross section, A = 2 *10-6 m2

Current carried by the wire, I = 3.0 A

From the relation I = nAe Vd where

e = Electric charge = 1.6 *10-19 C

Vd=Driftvelocity

We get Vd = InAe

Again, Drift velocity ( Vd) = Lengthofthewire(l)Timetakentocoverl(t)

t = lVd = lnAeI = 3*8.5*1028*2*10-6*1.6*10-193 = 27.2 *103 seconds

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