3.15 (a) Six lead-acid type of secondary cells each of emf 2.0 V and internal resistance 0.015 Ω are joined in series to provide a supply to a resistance of 8.5 Ω. What are the current drawn from the supply and its terminal voltage?
(b) A secondary cell after long use has an emf of 1.9 V and a large internal resistance of 380 Ω. What maximum current can be drawn from the cell? Could the cell drive the starting motor of a car?
3.15 (a) Six lead-acid type of secondary cells each of emf 2.0 V and internal resistance 0.015 Ω are joined in series to provide a supply to a resistance of 8.5 Ω. What are the current drawn from the supply and its terminal voltage?
(b) A secondary cell after long use has an emf of 1.9 V and a large internal resistance of 380 Ω. What maximum current can be drawn from the cell? Could the cell drive the starting motor of a car?
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1 Answer
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3.15 (a) Number of secondary cells, n = 6
emf of each secondary cell = 2 V
Internal resistance of each secondary cell, r = 0.015 Ω
Resistance of the resistor, R = 8.5 Ω
Current drawn from the supply, I is given as I =
= = 1.396 A
(b) Terminal voltage = I = 1.396 = 11.87 V
After long use emf = 1.9 V
Internal resistance of the cell, r = 380 Ω
Maximum current can be drawn = = 5 A
No, the cell cannot drive the starter motor of the car as it requires high current.
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