3.3 (a) Three resistors 1 Ω, 2 Ω, and 3 Ω are combined in series. What is the total resistance of the combination?

(b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

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6 months ago

3.3 (a) The equivalent resistance of the resistor in series is given by

R = 1 + 2 + 3 = 6 Ω

(b) From Ohm's law, I = VR we get I = 126 = 2 A.

Potential drop across 1 Ω resistor = I *R = 2 *1 = 2 V

Potential drop across 2 Ω resistor = I *R = 2 *2 = 4 V

Potential drop across 3 Ω resistor = I *R = 2 *3 = 6 V

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Physics Ncert Solutions Class 12th 2023

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